The speed-time graph of a 3500g
cart is shown on the left. A force acts to slow the cart down from 23m/s
to 10m/s.
What is the force acting over the 14 second period?
Step
1 = Change mass into kilograms
3500g = 3.5Kg
Step 2
Calculate the deceleration.
deceleration = change in speed/period of time
Change in speed = final speed - initial speed =
10 -23= -13m/s (the negative sign indicates deceleration)
Period of time = 14 seconds
Step 3
Acceleration = -13m/s/14/s = 0.93 m/s/s
The force = 3.5kg X 0.93m/s/s = 3.25 Newtons
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Incorrect
Some hints.
The formula you should use is
F =ma
The acceleration is the change
in speed over time.
Calculate the acceleration.
The acceleration is the gradient (slope) of the speed-time graph.
(Initial speed - final speed ) / time taken (seconds)=acc.
The mass of the cart is given as 3500g.
Change the mass of the cart into kilograms.
![]()
Incorrect
Some hints.
The formula you should use is
F =ma
The acceleration is the change
in speed over time.
Calculate the acceleration.
The acceleration is the gradient (slope) of the speed-time graph.
(Initial speed - final speed ) / time taken (seconds)=acc.
The mass of the cart is given as 3500g.
Change the mass of the cart into kilograms.
![]()
Correct
The force slowing the cart down has a magnitude of 3.25 Newtons
![]()
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Force and acceleration F=ma |
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![]() |
The
speed-time graph of a 3500g cart is shown on the left. A force acts to
slow the cart down from 23m/s to 10m/s.
|