Volumetric analysis

Backtitration

exercise 2

5.00g sample of impure limestone is treated with 150.0mL of 0.910M HCl. The reaction takes place according to the equation below.

After the reaction is complete it is found that 18.10mls of a 1.40M sodium carbonate is required to neutralise the unreacted acid.

Calculate the percentage of calcium carbonate in the sample.

(Ca =40.0, C= 12.0, O=16.0, CL =35.5, H =1.0)

Click for more detail.

 
Volume
Start
12.02mls
Finish
30.12 mls
Total
18.10mls

Continue with another exercise

 

Home