Volume = 3.5 X 22.4 = 78.4L
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mole = V/22.4 =
11.2/22.4 =0.5
mass = mole X molar mass = 0.5 X 28 =14 grams
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mole = V / 22/4 = 56.8 / 22.4 = 2.54 mole
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Step 1 calculate the mole of gas
=> mole = V / 22.4 = 11.2 / 22.4 = 0.5
Step 2 calculate the molar mass
M =m / mole = 35 / 0.5 =70 grams/mole. This is close to the molar mass of
chlorine.
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Standard
temperature and pressure.
S.T.P. 

The volume occupied
by one mole of any gas
at standard temperature(0^{o}) and pressure(1 atm) is 22.4 litres.
This volume is a close approximation and different gases vary slightly. 

The molar volume of any gas at S.T.P. is 22.4L .The mole of any gas can therefore be found using the expression on the right. Lets do some examples. 

Example 1 Example 2 Example 3


Try these exercises. 
